b^2-10b+18=2

Solution for b^2-10b+18=2 equation:

Simplifying
b2 + -10b + 18 = 2

Reorder the terms:
18 + -10b + b2 = 2

Solving
18 + -10b + b2 = 2

Solving for variable 'b'.

Reorder the terms:
18 + -2 + -10b + b2 = 2 + -2

Combine like terms: 18 + -2 = 16
16 + -10b + b2 = 2 + -2

Combine like terms: 2 + -2 = 0
16 + -10b + b2 = 0

Factor a trinomial.
(2 + -1b)(8 + -1b) = 0

Subproblem 1
Set the factor '(2 + -1b)' equal to zero and attempt to solve:

Simplifying
2 + -1b = 0

Solving
2 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1b = 0 + -2
-1b = 0 + -2

Combine like terms: 0 + -2 = -2
-1b = -2

Divide each side by '-1'.
b = 2

Simplifying
b = 2
Subproblem 2
Set the factor '(8 + -1b)' equal to zero and attempt to solve:

Simplifying
8 + -1b = 0

Solving
8 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + -1b = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -1b = 0 + -8
-1b = 0 + -8

Combine like terms: 0 + -8 = -8
-1b = -8

Divide each side by '-1'.
b = 8

Simplifying
b = 8
Solution
b = {2, 8}